How does Try and Catch exception handling run in Java?

Question

Aryan Kumar · Answer

The try-catch exception handling mechanism in Java works as follows:
The try block contains the code that could potentially throw an exception.If an exception is thrown in the try block, the exception is caught by the
catch block.The catch block executes the code that handles the exception.If the try block does not throw an exception, the catch block is skipped.
The catch block can be used to handle any type of exception. However, it is often used to handle specific types of exceptions. For example, the following code uses a
catch block to handle the ArithmeticException exception:
Java
try {
  int x = 10;
  int y = 0;
  int z = x / y;
} catch (ArithmeticException e) {
  System.out.println("Division by zero");
}
In this code, the try block contains the code that could potentially throw an
ArithmeticException exception. If the y variable is equal to 0, then the
ArithmeticException exception will be thrown. The catch block will then be executed, and the message "Division by zero" will be printed.
If the y variable is not equal to 0, then the ArithmeticException exception will not be thrown. In this case, the
try block will execute normally, and the catch block will be skipped.
The try-catch exception handling mechanism is a powerful tool that can be used to handle exceptions in Java. By using
try-catch blocks, you can ensure that your code is robust and handles errors gracefully.

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How does Try and Catch exception handling run in Java?

Revati S Misra

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